Finding Vrms given pressure, density and Temperature

AI Thread Summary
To find the root mean square velocity (Vrms) of a gas at 273K and 0.01 atm with a density of 1.24 x 10^-5 g/cm^3, the ideal gas law can be applied. The equation Vrms = sqrt(3RT/M) requires the molar mass (M), which can be derived from the gas density and the ideal gas law. The relationship between density, volume, and moles indicates that the volume does not affect the Vrms calculation if temperature and pressure remain constant. Understanding how to manipulate the ideal gas law is crucial for solving this problem. The discussion emphasizes the importance of relating density to molar mass to find the necessary variables for calculating Vrms.
sckeen1988
Messages
15
Reaction score
0

Homework Statement


At 273K and .01 atm, the density of a gas is 1.24*10^-5 g/cm^3. Find the Vrms for the gas molecules.


Homework Equations



Vrms=sqrt(3RT/M) Density=m/V

The Attempt at a Solution



I tried to relate the density given to the molar mass or the number of moles somehow, but failed completely.
 
Physics news on Phys.org
Use the ideal gas law (assuming it is an ideal gas).
 
How can I get volume from that?
 
Hint: does the answer really depend on the volume? E.g., if you find the solution for 1 cubic meter of this gas, will you find a different solution for, say, 2 cubic meters, if all of the other given properties are the same?
 
Thanks a lot for your help.
 
pls enlighten me on how you re-solve this. I don't understand on ohw do you use ideal gas law to resolve this.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top