- #1
Nick Bruno
- 99
- 0
1. Homework Statement [/b]
See attached
2. Homework Equations
See attached
3. The Attempt at a Solution
I know the answer is 6 or zero... but I can't figure out how to "show" this. When typing this equation into my calculator, I can clearly see that the number always ends in .0 or .6.
Initially I let k = (n-(n-1))
so the equation turns into
(n-(n-1))*([n-(n-1)] +1) / n = n(n-1)/n (1)
I then solve for n and I get
n^2 + 3n - 2 = 0
My calculator produces results
n^2 + 3n + 2 = 0.
Is equation (1) the correct way to solve this problem? If it is, the I just have a sign error somewhere... but I've triple checked my work and it seems there is none, so I am assuming (1) is not correct. Any suggestions?
See attached
2. Homework Equations
See attached
3. The Attempt at a Solution
I know the answer is 6 or zero... but I can't figure out how to "show" this. When typing this equation into my calculator, I can clearly see that the number always ends in .0 or .6.
Initially I let k = (n-(n-1))
so the equation turns into
(n-(n-1))*([n-(n-1)] +1) / n = n(n-1)/n (1)
I then solve for n and I get
n^2 + 3n - 2 = 0
My calculator produces results
n^2 + 3n + 2 = 0.
Is equation (1) the correct way to solve this problem? If it is, the I just have a sign error somewhere... but I've triple checked my work and it seems there is none, so I am assuming (1) is not correct. Any suggestions?