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(dy/dx)x + 2y = x^3.ln(x)

(dy/dx) = (x^3.ln(x) - 2y)/x

Integrating factor = x^2

(dy/dx)x^2 + 2xy = (x^3.ln(x))x^2

yx^2 = INT[(x^3.ln(x))x^2]

I'm having trouble integrating the last part to complete it.

Thanks alot and in advance for any help.