Fixing an Incorrect Equation Answer

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The discussion focuses on calculating the gravitational potential energy (GPE) change when moving from the Earth's surface to a height of 424 km. The correct formula for GPE is given as U_{GPE} = -GMm/r, with the zero reference set at infinity. For small height changes near the Earth's surface, the approximation U_{GPE} = mgh can be used, but for larger distances, the exact formula is necessary for accuracy. A calculation yielded an answer of -8.71*10^15, prompting a discussion on whether this is correct and how to present the answer with appropriate significant figures and units. The importance of verifying calculations with both the approximate and exact methods is emphasized for accuracy.
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Homework Statement
How much gravitational potential energy is required to lift a 9270-kg Progress spacecraft to the altitude of the International Space Station, 424 km above the surface of the Earth?
Relevant Equations
gpe=mgh
I tried just using that equation but I apparently didn't get the correct answer.
 
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The exact expression for GPE, with the zero reference set at infinity, is ##U_{GPE} = -\frac{GMm}{r}##. If we are at the surface of the Earth and consider a small change in ##r##, then ##\delta U = gm \delta r## is approximately correct and we say ##U_{GPE} = mgh##, once we set our zero reference somewhere suitable near the surface of the Earth. This is just an approximation, however.

Since ##424 \text{km}## is quite a long way, you'll need to find ##\Delta U_{GPE}## with the exact expression to get a more reasonable answer!
 
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etotheipi said:
The exact expression for GPE, with the zero reference set at infinity, is ##U_{GPE} = -\frac{GMm}{r}##. If we are at the surface of the Earth and consider a small change in ##r##, then ##\delta U = gm \delta r## is approximately correct and we say ##U_{GPE} = mgh##, once we set our zero reference somewhere suitable near the surface of the Earth. This is just an approximation, however.

Since ##424 \text{km}## is quite a long way, you'll need to find ##\Delta U_{GPE}## with the exact expression to get a more reasonable answer!
So with that equation I got an answer of -8.71*10^15. Does that sound right to you? I'm supposed to answer with 3 sig figs and units.
 
Try and also show your work, otherwise it's not obvious what calculation you've performed :wink:

You're after a change in GPE from radius of ##R_{E}## to ##R_{E} + 424 \text{km}##. So first of all, this is going to be a positive number.

The expression is ##U_{grav} = -\frac{GM_{E}m}{r}##, so you should be able to substitute in the two values of ##r## and subtract to get your change. Or better yet, do it algebraically and substitute in at the end!
 
high schoolphysics said:
So with that equation I got an answer of -8.71*10^15. Does that sound right to you? I'm supposed to answer with 3 sig figs and units.
The GPE equation above give the value relative to a point an infinite distance from the source of gravity ( where GPE is considered zero). What you want is the difference in GPE between two points.
 
so what are the units??
Also just use mgh first as sanity check...it should be within 7%(424/6000) of exact answer (not quite 3 sig fig!). Then do the exact using 1/r
 
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