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## Homework Statement

base of pyramid is a 6m x 6m square height of pyramid is 4meters. a 52 N/C E field orthogonal to the base of the pyramid

## Homework Equations

EA cos theta

## The Attempt at a Solution

if flux through base = EAcos theta = 52 (36m^2) cos(0) = 1872 N m^2 / C

Area of face of pyramid is 1/2 base x height = (.5)(6)(4) = 12

angle of normal to surface and E field is cos-1(3/5)

Why is flux through each surface not equal to the following:

so flux through one surface is = 52 N/C x 12m x cos(53.1) = 374.6

374.6 x 4 = 1498 N/ C

how do i derive flux through each face?