Flux through an infinite plane due to a point charge

AI Thread Summary
To determine the electric flux through an infinite plane due to a point charge located a distance d from it, the total flux through an enclosing cuboid is calculated as q/ε₀. The flux through the two infinite planes opposite the charge is negligible because the electric field approaches zero at infinity. Consequently, the flux through one infinite plane is derived to be q/(2ε₀). The key point is that the electric field's influence diminishes with distance, leading to this conclusion. Understanding the behavior of electric fields at infinity is crucial for accurate calculations.
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Homework Statement


A point charge q is located a distance d meters from an infinite plane. Determine the electric flux through the plane due to the point charge.
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Homework Equations

The Attempt at a Solution


I consider another infinite plane at a distance d in the opposite direction. Now I have infinite cuboid.

The flux through all the surfaces of the cuboid is ## \frac {q } { \epsilon _0} ##.

Since the plane with length d is smaller than the other two planes, the flux through these two planes is negligible in comparison with that due to the other two infinite planes. The other two infinite planes have equal flux. So, the flux through one infinite plane is ## \frac {q } { 2 \epsilon _0} ##.

Is this correct?
 
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Not quite right. It is not because the size is negligible but the electric field is zero at infinity.
 
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Yes, the other two surfaces are at an infinite distance from the charge, so the electric field is negligible and hence the flux. Thanks for pointing it out.
 
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