Flux through the Surface of the Plane

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Homework Statement


Find the upward flux of F = <x + z, y + z, 5 - x - y>, through the surface of the plane 4x + 2y + z = 8 in the first octant.

Homework Equations


∫∫(-P(∂f/∂x) - Q(∂f/∂y) + R)dA
where the vector F(x,y) = <P, Q, R>, dA = dxdy
and where z = f(x,y) <-- f(x,y) is the function that undergoes partial differentiaion

The Attempt at a Solution


F(f(x,y)) = <8 - 3x - 2y, 8 - 4x - y, 5 - x - y>
∂z/∂x = -4, ∂z/∂y = -2
∫∫(53-21x-11y)dxdy evaluated from x = 0 to x = 2 and y = 0 to y = 4 (shadow on the xy plane of the function 4x + 2y + z = 8)

My final answer is 80. The answer is 292/3. What am I doing wrong?
 
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Never mind. The mistake I made was integrate from y = 0 to y = 4 when it should have been from y = 0 to y = -2x + 4.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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