So in an application like this: The coil of the motor will, by Lenz's Law, induce a very large negative voltage across its terminals. Would this voltage be very negative at the left terminal of the inductor and very positive at the right? In this way the diode will conduct, but the negative voltage in this case would be directly connected to the power supply. Also, how are the flyback diodes in this way utilized[L293 - H Bridge IC]: It seems that the two left diodes will always be reversed biased, but what about the right-side two? Why are the left-side diodes even present if they are always reversed bias? It seems that the large negative voltage would forward bias one of the diodes to the right (whichever terminal is induced to a large negative potential), but what benefit does that have? Also, current flow back into the H-Bridge circuit does not appear very practical. Perhaps I am looking at this all wrong. EDIT: Given this situation: -Current flow from top to bottom -Pin 3 and pin 6 open circuited (transistor base = 0V) to turn off the motor Is it that a a positive voltage will be induced at the motor's "bottom" terminal and a negative voltage induced at the motor's "top" terminal? In this way, it seems that current would flow from the top diode from ground through the motor and then through the bottom left diode back into the source .. is that practical? How is this current limited? Current through a diode is unrestricted.