Flywheel Angular Velocity Problem

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Homework Help Overview

The problem involves calculating the angular velocity required for a flywheel to store a specific amount of energy, specifically in the context of rotational kinetic energy. The scenario presents a flywheel with given mass and radius, and the energy to be stored is derived from a typical gasoline consumption over a distance.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply the formula for rotational kinetic energy and calculates the angular velocity, but expresses uncertainty about the correctness of their approach and results.
  • Some participants question the moment of inertia used in the calculations, suggesting a possible error in the original poster's understanding.
  • Others point out a potential factor of √2 that may have been overlooked in the calculations.

Discussion Status

The discussion is ongoing, with participants providing hints and questioning assumptions without reaching a consensus. There is acknowledgment of a possible error in the calculation process, and some guidance is offered regarding the moment of inertia.

Contextual Notes

The original poster mentions working on the problem late at night, which may imply a lack of clarity or focus during their calculations. There is also a reference to a textbook answer that differs significantly from the original poster's result.

cchase88
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Homework Statement



A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provide a means of storing energy in the form of rotational kinetic energy and are being considered as a possible alternative to batteries in electric cars. The gasoline burned in a 300 mile trip in a typical mid-sized car produces about 1.2x10^9 J of energy. How fast would a 13kg flywheel with a radius of 0.3m have to rotate to store this much energy? Give your answer in rev/min


Homework Equations


Rotational Kinetic Energy (KEr) = (1/2)Iw^2
where I = mr^2


The Attempt at a Solution


So doing some basic algebra, and solving for w, I came up with:

w = sqrt(KEr/.5mr^2)

w = sqrt(1.2x10^9J / .5(13kg)(.3m^2)

w = 45291 rad/s

(45291 rad/s) / 2pi = 7208 rev/s * 60s = 432497 rev/min

The answer that the book is providing is: 6.1x10^5 rev/min

I'm not sure what I'm doing wrong, or If this is even the correct approach I should be taking to solve this problem.

Any help would be greatly appreciated.
 
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Welcome to PF cchase88,
cchase88 said:
where I = mr^2
Are you sure that's the moment of inertia of a disk about an axis passing through it's centre?
 
Hootenanny said:
Welcome to PF cchase88,

Are you sure that's the moment of inertia of a disk about an axis passing through it's centre?

tiny-tim said:
Hi cchase88! Welcome to PF! :smile:

Have you noticed you're out by a factor of √2? :rolleyes:

When in doubt, wkikpedia is often helpful

Thank you both for your help. I forgot about that 1/2. I guess that's what I get for doing a problem at 4 in the morning :rolleyes:
 
:zzz: cchase 88 z's ! :zzz:​
 

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