- #1
RichMortimer
- 26
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A solid circular flywheel around which a string is wrapped. At the end of the string is a 2 kg mass. If the mass is dropped, the drum will rotate.
After the mass has fallen h metres, it has a velocity of v m/s and the wheel has a rotational velocity of ω rad/s
The flywheel radius is 120 mm. Use principle of conservation of energy to show that the distance fallen h, and the velocity v, are related by the equation h = v^2(0.051+1.77xI)
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Right then,
Firstly, please don't give the answer as I would like to work it out. However, I'm a little lost on the direction to go.
Conservation = mgh = 1/2mv^2+1/2Iω^2
We have no height, Inertia, radius of gyration or time... So how can we start?
I've thought about substitution but do I just pluck a number? See's to random to do that?!
I'm assuming I can substitute equations into the above equation but yet still don't seem to have the relevant information.
As I said, not after the answer, just a kick in the right direction if possible.
P.S. That's all the information... no more!
Thanks in advance.
After the mass has fallen h metres, it has a velocity of v m/s and the wheel has a rotational velocity of ω rad/s
The flywheel radius is 120 mm. Use principle of conservation of energy to show that the distance fallen h, and the velocity v, are related by the equation h = v^2(0.051+1.77xI)
-----------------------------------------------------------------------------------------
Right then,
Firstly, please don't give the answer as I would like to work it out. However, I'm a little lost on the direction to go.
Conservation = mgh = 1/2mv^2+1/2Iω^2
We have no height, Inertia, radius of gyration or time... So how can we start?
I've thought about substitution but do I just pluck a number? See's to random to do that?!
I'm assuming I can substitute equations into the above equation but yet still don't seem to have the relevant information.
As I said, not after the answer, just a kick in the right direction if possible.
P.S. That's all the information... no more!
Thanks in advance.