Football 2D Motion: Time in Air

Thread starter PhysicsCCR
Start date Feb 6, 2012
Tags

2d 2d motion Air Motion Time

AI Thread Summary

A football is kicked at a speed of 19.8 m/s and an angle of 33.8° from ground level. The main challenge discussed involves determining the time the football remains in the air and the final horizontal distance it travels. Initially, there was confusion regarding how to calculate the time without knowing the final horizontal distance. The poster ultimately resolved their issue and found the solution. The discussion highlights the importance of understanding projectile motion in physics.

Feb 6, 2012

PhysicsCCR

A football is kicked at ground level with a speed of 19.8 m/s at an angle of 33.8° to the horizontal. How much later does it hit the ground?

Physics news on Phys.org

Feb 6, 2012

PhysicsCCR

I have attempted the problem, but I have two unknown variables: x final and t. I'm trying to find t, but how can I find x final first?

Feb 6, 2012

PhysicsCCR

Never mind. I figured it out.

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »