Force acting on steel rod (deformation)

AI Thread Summary
The discussion focuses on understanding the forces acting on a steel rod, specifically the values of P1, P2, and P3. It highlights that there are three forces: 300 kN, 180 kN, and 120 kN, and emphasizes the need for static equilibrium, which requires a force from the wall at one end of the rod. Participants suggest using a force balance to determine the reaction force at the left end and clarify the relationships between the forces. The conversation also touches on the method of creating a tension force diagram for better visualization. Ultimately, understanding the equilibrium of forces is crucial for solving the problem effectively.
foo9008
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in this problem , i could only understand that P3 = 120KN , i can't understand why P2= -60kN and why P1 = 240kN ? can someone explain ?

Homework Equations

The Attempt at a Solution

 

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In the same way that you can do a shear force diagram for lateral loads on a beam you can do a tension force diagram for axial loads on a shaft .

Basically plot a graph of axial tension against position along shaft . Have a try .
 
Nidum said:
In the same way that you can do a shear force diagram for lateral loads on a beam you can do a tension force diagram for axial loads on a shaft .

Basically plot a graph of axial tension against position along shaft . Have a try .
What do you mean? can you explain further?
 
If you do a force balance on the entire rod, what do you get for the reaction force on the left end?
 
Chestermiller said:
If you do a force balance on the entire rod, what do you get for the reaction force on the left end?
how to do it ? i know only the P3 ... which is 120kN , how to do for P1 and P2 ?
 

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foo9008 said:
how to do it ? i know only the P3 ... which is 120kN , how to do for P1 and P2 ?
You have 3 forces acting on the rod: 300 kN, 180 kN, and 120 kN. In order of the rod to be in static equilibrium, there must also be a force applied by the wall on the bar at location A. What does that force have to be?
 
Chestermiller said:
You have 3 forces acting on the rod: 300 kN, 180 kN, and 120 kN. In order of the rod to be in static equilibrium, there must also be a force applied by the wall on the bar at location A. What does that force have to be?
what i found is this ? how to find the force applied by the wall on the bar at location A. ??
btw , i am not sure which 1 is P3 and which one is P2
 

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foo9008 said:
what i found is this ? how to find the force applied by the wall on the bar at location A. ??
btw , i am not sure which 1 is P3 and which one is P2
Forget about P1, P2, and P3 for now. Are you saying that you don't know how to do a 1 dimensional equilibrium force balance on a solid object?
 
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Chestermiller said:
Forget about P1, P2, and P3 for now. Are you saying that you don't know how to do a 1 dimensional equilibrium force balance on a solid object?
yes
 
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Rod.PNG


F = 300 -180 + 120
 
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