Force between 2 parallel plates

AI Thread Summary
To find the force between two parallel conducting plates with charges Q1 and Q2, Gauss' Law can be applied to calculate the electric field between the plates. The electric field can be determined from one plate and then the superposition principle is used to account for both plates. The force exerted by one plate on the other is calculated using the formula F = qE, where q is the charge on one plate and E is the electric field created by the other plate. It is noted that the force is independent of the distance between the plates, which is an interesting aspect of the problem. Overall, the discussion clarifies the steps needed to solve the problem effectively.
khfrekek1992
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Homework Statement


Two parallel sheets of conducting metal are very close to each other (A>>d), they have charges of Q1 and Q2 on them. What is the force between these two plates?


Homework Equations


Gauss' Law


The Attempt at a Solution


From what I understand, you can use Gauss' law to calculate the field between the plates, but I don't know how to go about doing this. Any suggestions?

Thanks so much in advance!
 
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Start with one plate and use Gauss to calculate the electric field (like in Delphi's first link).
Then add the second plate and use the superposition principle, meaning you can simply add the electric field of both plates.
 
khfrekek1992 said:

Homework Statement


Two parallel sheets of conducting metal are very close to each other (A>>d), they have charges of Q1 and Q2 on them. What is the force between these two plates?

You gave hints to get the electric field strength between the plates. Is not the force between the plates asked?

ehild
 
@ehild: Yep, you're right. :)

So take one plate, say Q1, and calculate the electric field.
Then multiply by the charge of the other plate Q2.
The result is the force (F=qE) that Q1 exerts on Q2.
 
Wow! Thank you so much Delphi51, I Like Serena, and ehild! This makes so much sense now, the problem is a lot easier than I thought it would be... (Sorry I wasn't on for so long after I posted the question.) But thank you so much for all the help! That helps so much! :) You guys rock!
 
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