Force in The X direction using Lever Arm

AI Thread Summary
To determine the force needed to move a 500 lb car 3 inches forward using a 12-inch lever arm, the moments about the axle must be calculated. The equation derived is (3*500) - 12(Fx), leading to an initial force estimate of Fx = 125 lbs. However, this value appears high given the context of the problem. The discussion highlights the need to clarify the mechanics involved in using the lever arm to achieve the desired movement. Understanding the relationship between the lever arm length and the force applied is crucial for accurate calculations.
drummer8807
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Homework Statement



What is the Force Needed in the X direction?

I have a 500 lb Car and attached to the Wheel axle is a 12 inch long lever arm going straight down. The pivot point is at the axle and a cylinder is pushing the arm at the end of it. What force do I need to push this 500 pound car 3 inches forward?

Homework Equations





The Attempt at a Solution


Do I sum the moments about that axle at which I would get (3*500)-12(Fx) where Fx=125lbs...that number seems high...
 
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welcome to pf!

hi drummer8807! welcome to pf! :smile:
drummer8807 said:
What is the Force Needed in the X direction?

I have a 500 lb Car and attached to the Wheel axle is a 12 inch long lever arm going straight down. The pivot point is at the axle and a cylinder is pushing the arm at the end of it. What force do I need to push this 500 pound car 3 inches forward?

i don't understand the question :confused: …

horizontally, an insect could push it (slowly!)
 
How much force if I push on that lever arm do I need to move it 3 inches is what I am suppose to find out...
 
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