Force of interaction between two halves of a cylinder of charge.

AI Thread Summary
The discussion focuses on calculating the force of interaction per unit length between the upper and lower halves of a uniformly charged cylinder. The expected solution is given as ρ²R³/3ε₀. Participants express frustration over the lack of an analytic expression for the electric field of half a cylinder and discuss the assumption that the separation between the halves is zero, which simplifies the problem to that of an infinitely long cylinder. There is confusion regarding the correct approach to set up the problem, particularly in relation to finding the electric field and interaction energy. Ultimately, the challenge lies in accurately deriving the electric field and force from the given parameters.
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Homework Statement


Find the force of interaction per unit length between the upper and bottom halves of a cylinder of uniform charge density rho.


Homework Equations



Solution should be \rho^2R^3/3\epsilon_0


The Attempt at a Solution



Frustrated cause I've solved this problem in the past and don't recall how to do it.

There's no analytic expression for the field of half a cylinder yes? How would I start to set the problem up? Would I have to find the interaction energy first then take its gradient?
 
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There's no analytic expression for the field of half a cylinder yes? How would I start to set the problem up? Would I have to find the interaction energy first then take its gradient?

I think the problem is assuming that the separation between the two halves is 0. If not, it would have given you the separation, which it didn't. So the field is just the field inside an infinitely long cylinder.
 
ideasrule said:
I think the problem is assuming that the separation between the two halves is 0. If not, it would have given you the separation, which it didn't. So the field is just the field inside an infinitely long cylinder.

For the E field I just divided my expression for charge inside\rho.r^2/R^2 by the surface of a finite cylinder 2pi*rL. Doesn't get me anywhere near the answer.
 
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