Force of water on a pulled barge with angle

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SUMMARY

The discussion centers on calculating the force exerted on a barge by water when a horse pulls it with a force of 7900 N at an angle of 18°. The barge has a mass of 9200 kg and accelerates at 0.10 m/s². The net force acting on the barge is determined using Newton's second law (f=ma) and trigonometric functions to resolve the forces into components. The solution involves calculating the force of water as the unknown variable in the equation.

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Homework Statement



Suppose that the horse pulls on the rope with a force of 7900 N at an angle of 18° to the direction of motion of the barge, which is headed straight along the canal. The mass of the barge is 9200 kg, and its acceleration is 0.10 m/s2. What are the magnitude and the direction of the force on the barge from the water?



(a) Magnitude


(b) Direction (counterclockwise from the +x axis is positive)


Homework Equations



f=ma
trigs


The Attempt at a Solution



I trigged it;

(mass of the barge x the acceleration)-force of the horse cos (angle) = nope
 

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What forces act on the barge? (The force of the water will be your unknown.) What's the net force on the barge? Set the net force = ma. Consider components parallel and perpendicular to the direction of motion.
 
ohhhhhh
thank you so much !
 

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