Force on a pure oxygen bubble in air by a magnet

Gnorrell
Messages
3
Reaction score
0
There are the famous experiments, which show, how an Oxygen soap bubble gets attracted by a magnet due to it's paramagnetism. And how a Nitrogen bubble gets repelled by it (in air)But how does one calculate the attraction force of this pure Oxygen soap bubble in air due to a magnet.

I'm Sorry, this isn't directly a homework. But I really want to be able to calculate this, as I found this experiment very astounding. But unfortunately I lack the ability to calculate it.

I would think I have to calculate the force on one O2 molecule due to the magnet and then sum it up over the volume of the bubble with the corresponding O2 density. Then I have to subtract the O2 density of the air from it (as it wouldn't be attracted if it has the same O2 concentration), to get the total force.

But how does one calculate the force on a single O2 molecules due to a magnet. And is only the magnetic (field) strength important here for the force developed or also the inhomogenity. I would expect that in a homogeneous m-field there would be no force.

Thanks for any answers or hints on how to solve this problem.
 
Physics news on Phys.org
Oxygen has a high degree of paramagnetism due tio the fact that its outer two electrons' spins are not paired.

You are correct in assuming that it would take an inhomogeneous magnetic field to attract an oxygen bubble. Which of course you get from an ordinary bar magnet.

Computing the magnetic moment of an oxygen atom is beyond what I know. I refer you to
http://en.wikipedia.org/wiki/Magnetic_moment for the computation of the magnetic moment of an electron. The formula is simple but determining the spin of the electron is what I don't know how to determine.

BTW be sure to take note of the quantum electrodynamic correction to the Dirac g-factor in order to avoid an error of 0.1%.

I love this job. :-)
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top