Force on charge and electric field question

AI Thread Summary
To determine the force on charge g0 and the electric field at the origin due to the charge bar, it's essential to clarify whether the bar represents a continuous line of charge or two separate point charges. If it's a continuous charge distribution, integration using Coulomb's law is necessary to calculate the electric field. If it's two point charges, summing the forces from each charge will suffice. The discussion suggests using Coulomb's law for calculations and applying the formula F = qE to find the force once the electric field strength is established. Clarification on the course material covered may also be needed for further assistance.
XodoX
Messages
195
Reaction score
0

Homework Statement



http://img521.imageshack.us/img521/1996/physicsz.jpg

Homework Equations


The Attempt at a Solution

I hope the drawing is somewhat clear. How do I find the force on the charge g0 and the electric field at the origin due to the charge bar? There's barely any information given. The first λ is at 7m and the second one at 10m. And you have 2 C at the origin. I do not know how to do this. I hope somebody can help me with this.
 
Last edited by a moderator:
Physics news on Phys.org
Hi,
A bit more information might be helpful. Is the bar a continuous line of charge, or two point charges separated by 3 metres. In the former case you need to integrate along the bar using for example Coulomb's law. In the latter case you just need to sum the forces from the two charges.
 
No idea. Looks like it has to be 2 separate charges. Otherwise, I wouldn't know what that would be. Can't find anything that would apply to that. I guess I will go with Coulomb's law then.
 
From your drawing and notations it looks like you have two diff. linear charge densities for two parts of the bar. So integration is necessary to find the Efield at the origin. After that you just do F =qE You would then know the electric field strength at the 2C charge so you got the force.

Have you gone this far in your course?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top