Force Profile of a Hinged Rod on the Ground

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Discussion Overview

The discussion revolves around the force profile exerted by a hinged rod lying on the ground when a torque is applied at the hinge. The focus is on understanding the distribution of forces along the length of the rod, assuming it is weightless.

Discussion Character

  • Exploratory, Homework-related, Mathematical reasoning

Main Points Raised

  • One participant proposes a formula for calculating the force at a given point along the rod, suggesting F = T/L, but expresses uncertainty about the distribution of force since the entire length of the rod is in contact with the ground.
  • Another participant notes that the force near the pivot will be greater than the force at the end of the rod, indicating a gradient in force distribution.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the exact force profile, and multiple views regarding the distribution of forces remain present.

Contextual Notes

The discussion does not clarify the assumptions regarding the torque application or the implications of the rod being weightless, leaving some mathematical steps unresolved.

arihantsinghi
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TL;DR
Torque, Distributed Load, Hinged Rod
A rod of length 'L' is hinged at one of its ends and is lying on the ground. A torque 'T' is applied to it at the hinge such that it pushes the rod into the ground. What will be the force profile on the ground since the entire length of the rod touches the ground? Assume the rod is weightless.
 
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Welcome! :smile:

Please, show your best attempt to answer the question, based on what you have learned about torque and distributed loads.
Thank you.
 
I can calculate the force on a given point by F = T/L. But, since the entire length is touching I am not sure. Force near the pivot will be more and at the end it will be the least.
 
Thread locked. @arihantsinghi, please post your homework request in the Homework Help section, under Intro Physics Homework, and including your effort to solve the problem.
Also, do not post the same problem more than once.
 

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