Force required to bend sheet metal with a bending brake

AI Thread Summary
The force required to bend sheet metal using a hand bending brake depends on factors such as the thickness of the metal, the bend radius, and the desired angle of the bend. For a .032" thick aluminum sheet measuring 3 feet long and bent to 110°, the specifics of the bend radius and edge sharpness play a crucial role in determining the force needed. Calculators available online can provide estimates based on these parameters. The volume of metal being deformed during the bend is also a critical consideration. Accurate calculations can help in achieving the desired bend effectively.
HCaduser
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I want to know the force required to bend a piece of sheet metal in a hand bending brake. The sheet metal is clamped down and then bent upwards to a desired angle. The action is performed in the video below . Let's say I wanted to bend a piece of .032" thick AL 3' long to 110° (given the brake was able to make this degree of bend). How much force would be required to make this bend using this bending method?

 
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"How much force?" Depends on the actual bend radius, how sharp an "edge" you have on the break.
 
"Edge" is a radius of .04" And the bend radius is .045".
 
What's the volume of metal in the bend that is being permanently deformed?
 
.11in^3
 
Last edited:
HCaduser said:
.032" thick AL 3' long
times
HCaduser said:
bend radius is .045".
times 2pi/4
HCaduser said:
6.912in^3
Don't think so.
 
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