Force resulting from a pressurized departing gas

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To determine the force exerted by gas escaping from a cylinder, the mass flow rate and gas velocity are crucial. The force can be calculated using the rate of change of momentum, which incorporates both the mass flow rate and the velocity of the gas. Given the mass flow rate of 69.33 lb/s and a gas velocity of 4000 ft/s, these values must be converted to SI units for accurate calculations. The discharge of 6.933*10^-5 lbs over a small time increment contributes to the overall force. Proper unit conversion and application of the momentum principle are essential for finding the resulting force on the cylinder.
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Hello,
Thank you for your help.

So if I have a cylinder with a hole in it, and gas escaping from it. How can I find the resulting force that gas is exerting on the cylinder. So I can then find the acceleration it is imparting.

I know the density of the gas 2.85 lb/ft^3, and the mass flow rate of the escaping gas is 69.33 lb/s.

In a very small increment of time .001 milliseconds. There has been 6.933*10-5 lbs discharged.

What is the resulting force on the cylinder? Is it just the lbs of Gas discharged? I know the velocity of the gas is around 4000 ft/s, do I need this to find this out? or is the mass flow rate accounting for it?

Thank you,
 
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I would say that you need to use force = rate of change of momentum
You should really be using SI units...m, kg, s
 
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