Force to Lift 10 Bags of Soil (185N each)

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To lift ten bags of soil weighing 185 N each, totaling 1850 N, two people must exert equal force on a 2.40 m long sheet of wood. The bags are stacked 0.50 m from one end, creating a moment arm that affects the force distribution. By treating the system as a moment arm, the forces exerted by each person must balance the total weight and the moments about the chosen pivot point. The calculations involve equating the total weight to the sum of the lifting forces and their respective distances from the pivot. Understanding these principles is crucial for determining the exact force each person must exert.
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Homework Statement



Ten bags of top soil, each weighing 185 N, are placed on a 2.40-m long sheet of wood. They are stacked 0.50 m from one end of the sheet of wood, as shown below. Two people lift the sheet of wood, one at each end. Ignore the weight of the wood, how much force must each person exert?

Homework Equations



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10*185=1850N so that would be the total being liften since the wood is ignored
From there I am stuck as to do what http://img120.imageshack.us/img120/6727/p827rs8.th.gif
 
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Treat it as a moment arm about one end or the other. Your choice.

The weight times the distance away from where you choose and the force times the length of the board must match shouldn't they? Since you know the total weight then you know the sum of the lifting forces must equal that.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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