Forces acting on a truck on a slope

AI Thread Summary
A truck with a mass of 5000 kg is positioned on a 45-degree slope and is subject to a horizontal external force while remaining stationary. The forces acting on the truck include gravity, the normal force from the ground, and the external force. The equilibrium condition is established with the equation combining these forces, leading to two key equations: one relating the ground force's sine component to the external force and the other relating its cosine component to the weight of the truck. By solving these equations, the magnitude of the ground force can be determined. The analysis concludes that the forces balance, confirming the truck's stability on the slope.
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Homework Statement


The truck is on the slope 45 degrees and on it is acting a horizontal external force. How big is the force of the ground if the mass of the truck is 5000 kg and the truck is not sliding down the slope?

Homework Equations


First of all I drew myself a sketch. Then I asked myself: Which forces are acting on the selected body (=truck). My answer was
1. force of gravity (because of the Earth)
2. Force of the ground (because the truck is in touch with the ground)
3. External force.
Is there anything else that affects a body? In my opinion no.

\vec{F_{ground}} + \vec{F_{gravity}} + \vec{F_{external}} = 0
( F_{ground}sin\alpha, F_{ground}cos\alpha ) + ( 0, -mg ) + ( -F_{external}, 0 ) = ( 0, 0 )
F_{ground}sin\alpha = F_{external}
F_{ground}cos\alpha = mg ... and from here I express equation for F_{ground}
 
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