Forces and the Laws of Motion HELP

AI Thread Summary
To determine the coefficient of kinetic friction for a 4.00 kg block pushed along the ceiling with an 85.0 N force at a 55.0-degree angle, it's essential to resolve the applied force into its horizontal and vertical components. The vertical component contributes to the normal force, while the horizontal component is responsible for the block's acceleration of 6.00 m/s². By calculating the necessary force to achieve this acceleration and comparing it to the horizontal component, the kinetic friction force can be established. The initial calculation suggested a coefficient of kinetic friction of 0.82, but further verification is needed to confirm this value. Understanding the application of trigonometry and the Pythagorean theorem is crucial for solving similar problems involving forces and motion.
covergirl
Messages
1
Reaction score
0
Forces and the Laws of Motion HELP!

Homework Statement


A 4.00 kg block is pushed along the ceiling with a constant applied force of 85.0 N that acts at an angle of 55.0 degrees with the horizontal. the block accelerates to the right at 6.00 m/s2. Determine the coefficient of kinectic friction between the block and ceiling.
m=4kg
Fnet=85N
a=6m/s2


Homework Equations


uk= Fk / Fn


The Attempt at a Solution


uk= Fk / 85.0 N
sin 55 = x/85
x=69.6
uk= 69.6/85 = .82
the coefficient of kinetic friction between the block and the ceiling would be .82??


is that right??

i know this is too much to ask, but can anyone PLEASE explain to me forces and laws of motion.?? pleaseeee. i need major help about these especially with problems that have the angles and coefficient of friction..

thankss :D
 
Physics news on Phys.org
In questions like this all you need to know is pythagorean theorem for finding the magnitudes of resulting forces and trigonometry for resolving forces.

First of all you need to resolve your force into the horizontal and vertical components using the magnitude of the force and the angle given. The normal force will of course be the vertical component. The horizontal component accelerates the block but is counteracted by the kinetic friction force. You can work out the force needed to accelerate the block at 6ms-2 and compare it to the horizontal component of force to find the kinetic friction force.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top