Forces Homework: Finding Work and Velocity

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SUMMARY

The discussion focuses on calculating work and velocity for a body with a mass of 1 kg subjected to a force of 5 N over a displacement of 4 m. The work done by the force is calculated using the formula Work = Force * Displacement, resulting in 20 J. To find the final velocity, the kinematic equation v² = v₀² + 2ax is applied, leading to a final velocity of approximately 6.32 m/s. The discussion emphasizes the importance of using kinematic formulas when time is not provided.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Familiarity with kinematic equations
  • Basic knowledge of work-energy principles
  • Ability to perform algebraic manipulations
NEXT STEPS
  • Study kinematic equations in-depth, particularly v² = v₀² + 2ax
  • Explore the relationship between force, mass, and acceleration in various contexts
  • Learn about energy transfer and work done in physics
  • Investigate real-world applications of Newton's laws in mechanics
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of work and velocity calculations in practical scenarios.

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Homework Statement


We have a body with mass=1kg and it's on rest. When a force of 5N acts on it , the body displaces 4m. Assume no friction
Find:
a)The work that force did
b)Velocity at the end of the distance(displace)
a)
##Work=Force * Displacement = 5N*4m = 20J##
##A=Fd=(5N)(4m)=20J##
b)
Uhm,
##F=\frac{mv}{t}##, i have no time given. My teacher said this has a solution, it's not wrong. I'm stuck here




The Attempt at a Solution


a)
##Work=Force * Displacement = 5N*4m = 20J##
##A=Fd=(5N)(4m)=20J##
b)
Uhm,
##F=\frac{mv}{t}##, i have no time given. My teacher said this has a solution, it's not wrong. I'm stuck here
 
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Look for a kinematic formula that relates velocity, acceleration, and distance, since those are the things you have to work with.
 
Ehm, maybe that would be:
##a=F/m##
##a=5N/1kg=5m/s^2##
##a=\frac{Δ v}{Δ t}##
##5m/s^2=\frac{v_1-0}{t}##
I have no v_1(which i have to find) and I have no time..
If so, would that be
##v^2=v_0^2+2ax## which gives us
##v^2=0m^2/s^2+2(5m/s^2)(4m)##
##v^2=40m^2/s^2##
##v=\sqrt{40}=6.324555320336759m/s##
 
That works!
 
thanks!
 

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