Forces, I want to get the magnitude of the acceleration for the following problem ple

AI Thread Summary
The problem involves two 2kg objects connected by a massless string, with one moving vertically and the other horizontally under a 10 N force at a 60-degree angle. The vertical object's acceleration is calculated using the equation T - mg = ma, while the horizontal object's forces are analyzed with 10cos60 - T = ma. The user initially obtained a negative acceleration value and questioned whether it should be considered positive. Responses confirm that the solution is correct, with the acceleration being negative indicating the direction of motion. The discussion emphasizes understanding the directional nature of acceleration in the context of the problem.
madinsane
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Question says.
Two objects of mass 2kg each are attached to each other by a massless string. One moves vertically and the other is moving on a frictionless surface horizontally and is being pulled the opposite direction by a force of 10 N at 60 degrees to the horizontal get the acceleration of each object and then get tension

My solution
Total fy for vertical object is
T-mg=ma
For the second I got forces in x direction as 10cos60 -T=ma
I then solved for a and got a negative answer then I substituted that value to get T. But should I have written a as positive? Is my solution correct
 
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you give {a} against the point.
(((One moves vertically))))moves down
your solution is correct
 


pymn_nzr said:
you give {a} against the point.
(((one moves vertically))))moves down
your solution is correct

thanks!
 
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