Forces, I want to get the magnitude of the acceleration for the following problem ple

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SUMMARY

The discussion centers on calculating the acceleration and tension in a system of two 2kg masses connected by a massless string, where one mass moves vertically downward and the other moves horizontally on a frictionless surface. The horizontal mass is subjected to a 10 N force at a 60-degree angle. The user correctly applied Newton's second law, resulting in equations for both masses: T - mg = ma for the vertical mass and 10cos(60) - T = ma for the horizontal mass. The user questioned the sign of the acceleration but received confirmation that their solution was correct.

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Question says.
Two objects of mass 2kg each are attached to each other by a massless string. One moves vertically and the other is moving on a frictionless surface horizontally and is being pulled the opposite direction by a force of 10 N at 60 degrees to the horizontal get the acceleration of each object and then get tension

My solution
Total fy for vertical object is
T-mg=ma
For the second I got forces in x direction as 10cos60 -T=ma
I then solved for a and got a negative answer then I substituted that value to get T. But should I have written a as positive? Is my solution correct
 
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you give {a} against the point.
(((One moves vertically))))moves down
your solution is correct
 


pymn_nzr said:
you give {a} against the point.
(((one moves vertically))))moves down
your solution is correct

thanks!
 

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