To answer this question, we need to consider the forces acting on the mass. In this case, there are two main forces: the normal force, which is perpendicular to the surface of the sphere, and the force of friction, which is parallel to the surface.
The normal force is equal to the weight of the mass, which is given by Fg = mg, where g is the acceleration due to gravity (9.8 m/s^2).
The force of friction is given by Ff = μN, where μ is the coefficient of friction and N is the normal force. In this case, μ = 0.6 and N = mg. So, Ff = 0.6mg.
Now, we need to consider the forces in the horizontal and vertical directions. In the vertical direction, the forces are balanced since the mass is not moving up or down. So, we can focus on the horizontal direction.
In the horizontal direction, we have the force of friction acting in the opposite direction of motion (since the mass is on the verge of sliding) and the component of the weight of the mass acting in the direction of motion.
Using trigonometry, we can determine that the angle between the weight and the horizontal direction is θ = tan^-1(0.6). So, the angle at which the mass will start sliding is approximately 31.8 degrees.
It's also important to note that this angle may change if the mass or the coefficient of friction changes. So, it's important to understand the concept and be able to apply it to different scenarios. I hope this helps with your test preparation. Good luck!