Fourier series and calculate integral

rayman123
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Homework Statement


expand the function in Fourier series and calculate the integral
f(x)= (sinx)^2(cosx)^3, 2\pi is the period
calculate the integral
\int_{0}^{2\pi}f(x)dx
please help...have absolutely no idea how to calculate it...


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Express the cos3(x) as (1 - sin2(x))cos(x) and use the substitution u = sin(x).
 
rayman123 said:

Homework Statement


expand the function in Fourier series and calculate the integral
f(x)= (sinx)^2(cosx)^3, 2\pi is the period
calculate the integral
\int_{0}^{2\pi}f(x)dx
please help...have absolutely no idea how to calculate it...
Note that f(x) is even, so what does this tell you about its Fourier expansion?

You can use trig identities to rewrite f(x) as a Fourier series, instead of having to crank out the integrals. In particular, look at the power-reduction formulas, and use what you know about what its Fourier expansion should look like to guide you.

http://en.wikipedia.org/wiki/List_of_trigonometric_identities
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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