Fourier series, applications to sound

robertjford80
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Homework Statement



Screenshot2012-06-18at13057AM.png



The Attempt at a Solution



I don't understand where that 2 comes from in the denominator in cos nπ/2
 
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robertjford80 said:

Homework Statement



Screenshot2012-06-18at13057AM.png



The Attempt at a Solution



I don't understand where that 2 comes from in the denominator in cos nπ/2

Instead of trying to follow somebody else's presentation, just sit down and do the integrations yourself. That way, you will answer your own question, and will *understand it much better than if somebody else showed you how to do it*. I really believe that.

RGV
 
of course i always do my own derivation. my own derivation is -cosnπ/524nπ - 1/524nπ

There, I'm still as clueless I was before.
 
robertjford80 said:
of course i always do my own derivation. my own derivation is -cosnπ/524nπ - 1/524nπ

There, I'm still as clueless I was before.

So, you claim that 524/1048 = 1? That is the only way you could end up with what you said.

RGV
 
ok, I got it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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