Here is the question:(adsbygoogle = window.adsbygoogle || []).push({});

At [itex] x= \frac{\pi}{2} [/itex] the square wave equals 1. From the Fourier series at this point find the alternating sum that equals [itex] \pi [/itex].

[tex] \pi = 4(1 - \frac{1}{3}+\frac{1}{5}-\frac{1}{7} + \ldots [/tex]

I do not understand what the question is asking. I'm not knowledgeable enough with Fourier series to understand it I believe. This is my best guess:

I need to find the fourier series of the square wave starting at [itex] \frac{\pi}{2} [/itex] fand this will "magically" yield the alternating series for [itex] \pi [/itex].

But I don't understand what "the square wave equals 1" part means. Do I define the square wave to jump to 1 at [itex] \frac{pi}{2} [/itex] instead of the typical wave (typical for me) where the wave is -1 from -pi to 0, and jumps to 1 at 0 to pi ?

Any help clarifying would be swell. Thanks :)

What's up with the LaTeX by the way?

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# Homework Help: Fourier series (I need help here)

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