Fourier transform - would appreciate if my answer can be checked

memorex88
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Homework Statement



Question: Find the Fourier series for

f(x) = x(2π-x) 0<x<2π f(x) = f(x+2π)hope the pi is clear as π

The Attempt at a Solution


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The constant term should be ##2\pi^2/3##, but other than that, your answer looks fine.

One easy way to check your answer is to simply plot the series using a computer.

By the way, you're finding a Fourier series, not a Fourier transform, which is a different but related concept.
 
Thanks Vela for checking, oops been doing both topics lately, slip of the tongue
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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