Fraction of energy dissipated when solid cylinder placed on table

AI Thread Summary
A uniform solid cylinder spinning about its axis experiences energy dissipation due to sliding friction when placed on a rough horizontal table. The initial kinetic energy can be expressed using the equations 0.5mv^2 for translational motion and 0.5Iw^2 for rotational motion. As the cylinder transitions from sliding to rolling, a portion of its initial kinetic energy is lost to friction. The discussion concludes that the fraction of kinetic energy dissipated before the cylinder rolls smoothly is 2/3. This problem highlights the importance of conservation of angular momentum at the point of contact during the transition.
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A uniform solid cylinder is set spinning about its axis and is then gently placed, with the axis horizontal, on a rough horizontal table. What fraction of its initial kinetic energy is dissipated in sliding friction before the cylinder eventually rolls smoothly along the plane?

The only equations I think are needed are 0.5mv^2 and 0.5Iw^2, and I can write down equations for the total energy before and after, but cannot relate the two.

Apparently the answer is 2/3.

Thanks
 
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Think conservation of angular momentum with respect to the point of contact.
 
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