Frame of reference question: Car traveling at the equator

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A car traveling west at 460 m/s at the equator experiences different speeds depending on the reference frame used. In an inertial frame centered on Earth, the car's speed is effectively zero as it moves along a curved path due to Earth's rotation. In a rotating frame, the car's weight is influenced by centrifugal and Coriolis forces, which alter the apparent gravitational force acting on it. The Coriolis force, which acts perpendicular to the velocity vector, has both vertical and horizontal components depending on the latitude, affecting the car's motion. Understanding these dynamics is crucial for accurately assessing forces and motion in different reference frames.
  • #31
haruspex said:
We seem to be having the same conversation on two concurrent threads. See my reply on the other.
Yes I see,now is clear.
Can object feels coriolis force ,same as you can feel centifugal force when driving car in curve?
When birds flight to the north,they bend to the right(east),they path is curved looking from satelite which rotate with Earth speed.
Do birds body feel centrifugal force because they travel at curve,if they fly with accelometer,will he notice Fc?
If we assume that birds flight is fast enough ..

Or this is just optical ilusion which can be seen only from rotating frame,so birds fly in straight line and their body don't feel centifugal force caused by curve path?

bird.jpg
 
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  • #32
John Mcrain said:
Can object feels coriolis force ,same as you can feel centifugal force when driving car in curve?
No. You cannot feel centrifugal force either. Nor can you feel gravity. Coriolis is the same.

What you can feel are the strains in your body as the car pushes you into the curve, or as the surface of the Earth pushes you upward against your otherwise downward trajectory.
John Mcrain said:
hen birds flight to the north,they bend to the right(east),they path is curved looking from satelite which rotate with Earth speed.
The effect of Coriolis on birds is entirely negligible. Just as it is on you when you walk down the aisle at the grocery store.

If Coriolis deflects you a half millimeter to the right, you correct course to avoid bumping into the tomato sauce and get to the end of the aisle without incident.

If Coriolis deflects a goose a couple of inches to the right, the goose corrects course to keep on its path. It takes a leftward bank angle too small to notice in order to maintain a straight-line flight path. Birds can deal with flying in a cross-wind; Flying with Coriolis is vastly easier.
John Mcrain said:
Do birds body feel centrifugal force because they travel at curve,if they fly with accelometer,will he notice Fc?
If we assume that birds flight is fast enough ..
Are we talking centrifugal or Coriolis here? Either way, the effect is too small to be noticed.

We can walk on a tilting floor with no problem. We can walk away from the table after eating a big meal without any problem. We can walk away from the toilet without any problem. Those are all things that are equivalent to centrifugal or Coriolis forces -- minor differences in the magnitude or direction of the inertial force of gravity. Things that you deal with without bothering to think about it.
 
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  • #33
jbriggs444 said:
The effect of Coriolis on birds is entirely negligible. Just as it is on you when you walk down the aisle at the grocery store.
Instead birds ,use missile.
Accelometer in missle will not show acceleration caused by curved path to the right?
If I am in missile which travel to the north ,will I feel same force as when car going in right turn?
 
  • #34
John Mcrain said:
Instead birds ,use missile.
Accelometer in missle will not show accelartion caused by curved path to the right?
If I am in missile which travel to the north ,will I feel same force as when car going in right turn?
Again, you cannot feel any centrifugal force in a right turn. None. Nada. Zilch. Zip. Never. Ever.

What you can feel is the car forcing you to deviate from your natural free-fall trajectory. The car supports you against gravity and pushes you around the turn. The stresses from those forces are what you can feel.

An accelerometer in a cruise missile can sense the acceleration resulting when the missile's guidance system commands a slight left bank to compensate for the rightward deflection from Coriolis.

An accelerometer in a ballistic missile would feel nothing. The operator would have commanded a launch angle enough leftward so that Coriolis would result in a hit without any mid-course maneuvering.
 
  • #35
jbriggs444 said:
Again, you cannot feel any centrifugal force in a right turn. None. Nada. Zilch. Zip. Never. Ever.

What you can feel is the car forcing you to deviate from your natural free-fall trajectory. The car supports you against gravity and pushes you around the turn. The stresses from those forces are what you can feel.

Ok will I feel missile force my body to the right ,because missile path is curved to the right looking from rotation frame?
 
  • #36
John Mcrain said:
Ok will I feel missile force my body to the right ,because missile path is curved to the right looking from rotation frame?
You feel the missile force your body to the left to maintain a "straight" course track over the rotating Earth. The natural un-forced trajectory would be a rightward curve.

This assumes a cruise missile. A ballistic projectile would be in free fall -- nothing to feel.
 
  • #37
jbriggs444 said:
You cannot feel centrifugal force
It depends what you mean.
Necessarily you work in your own reference frame; in that frame you have no velocity nor acceleration. If I feel an unbalanced horizontal normal force from the side of the car I'm in, my brain invents a countervailing force to explain the lack of acceleration. This I feel as centrifugal force.

For Coriolis, we can use the problem in this thread to create a theoretical example. Suppose I were on the equator of a small planet spinning so fast that it appreciably lowers the normal force from the ground. If I were to run at a comparable tangential speed in the same direction I would notice the normal becoming even less, i.e. Imwould feel as though I weighed less, but if Inwere to run the other way I would feel myself get heavier. You could say that I feel the Coriolis force.
 
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  • #38
John Mcrain said:
You mean with mid-course maneuvering ?
Yes. My assumption (not being a cruise missile expert) is that they follow a straight-line track relative to the rotating Earth and continually adjust their heading so as to keep the target on a fixed bearing. This will involve corrections for cross-wind and Coriolis, at least.
John Mcrain said:
But if missile is shoot slighlty leftward to target then during flight _I don't feel nothing inside?
Yes.

A typical ballistic missile burns all of its fuel promptly and then free-falls toward the target. Hence the term "ballistic". The result is very much like a naval gun. In the northern hemisphere you have to aim left to compensate for Coriolis. A passenger on the [short] flight would be in free fall all the way after engine burnout.

From the rotating frame, the picture is of a missile curving right to hit the target. From the non-rotating frame, the picture is of a missile on a straight-line path where the target rotates left to arrive under the missile at the time of impact.

There is also a vertical component to Coriolis which needs to be managed. Naval gun tables have corrections for both the right-left deflection and the up-down deflection.
 
  • #39
jbriggs444 said:
From the rotating frame, the picture is of a missile curving right to hit the target. From the non-rotating frame, the picture is of a missile on a straight-line path where the target rotates left to arrive under the missile at the time of impact. [There is also a vertical component to Coriolis which needs to be managed. Naval gun tables have corrections for both the right-left deflection and the up-down deflection]

Ok that mean curved path is just "ilusion" which appear in rotating frame..

But what about wind,is low pressure counterclok wise rotation can be seen from inertial(non-rotating) frame too or this is just appeare in rotating frame or in other words ,is wind really rotate counterclok wise?

How is cyclone at north hemisphere look like in inertial frame?
 
  • #40
John Mcrain said:
Ok that mean curved path is just "ilusion" which appear in rotating frame..
Yes, that is correct.
John Mcrain said:
But what about wind,is low pressure counterclok wise rotation can be seen from inertial(non-rotating) frame too or this is just appeare in rotating frame or in other words ,is wind really rotate counterclok wise?

How is cyclone at north hemisphere look like in inertial frame?
The Earth is really rotating. The air on the Earth, by and large, rotates with the Earth.

This rotation can be amplified. Like the whirlpool in your bathtub or a skater twirling on the ice. If water is drawn to the center or if the skater pulls in her arms, any pre-existing rotation increases in rate in order to conserve angular momentum. That's a real rotation which can be seen from both inertial and rotating frame.

This is the inertial frame's explanation for why low pressure zones rotate in the same direction as the Earth (clockwise in the northern hemisphere). The rotating frame notes that Coriolis deflects the inward-bound air. The air in the south is deflected east. The air in the east is deflected north. The air in the north is deflected west. The air in the west is deflected south. All of those are clockwise deflections. The result is a counter-clockwise circulation. [Edit, after correction by @John Mcrain]
 
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  • #41
jbriggs444 said:
This is the inertial frame's explanation for why low pressure zones rotate in the same direction as the Earth (clockwise in the northern hemisphere).
Low pressure-cyclone rotate in anti clock wise direction at north hemisphere.
This picture below is from rotating frame,camera is rotate with earth.
Perhaps this piture will looks like something different if camera is fixed at one point in space(inertial frame)

Agree?

1200px-Low_pressure_system_over_Iceland.jpg
 
  • #42
John Mcrain said:
Low pressure-cyclone rotate in anti clock wise direction at north hemisphere.
This picture below is from rotating frame,camera is rotate with earth.
Perhaps this piture will looks like something different if camera is fixed at one point in space(inertial frame)

Agree?

View attachment 270361
Right you are. Earth rotates counter-clockwise and so do low pressure zones. Brain fade on my part.
 
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  • #43
jbriggs444 said:
Right you are. Earth rotates clockwise and so do low pressure zones. Brain fade on my part.
How woould cyclon picture looks like in inertial frame(if camera is fixed at space)?
 
  • #44
John Mcrain said:
How woould cyclon picture looks like in inertial frame(if camera is fixed at space)?
You have the picture of a hurricane. A snapshot is a snapshot. Reference frame is irrelevant.

[At least until we get to special relativity and the relativity of simultaneity]
 
  • #45
jbriggs444 said:
You have the picture of a hurricane. A snapshot is a snapshot. Reference frame is irrelevant.

[At least until we get to special relativity and the relativity of simultaneity]
Ok does video of hurricane from fixed camera at space(inertail frame ) will looks the same as when camera is rotating with earth?
 
  • #46
John Mcrain said:
Ok does video of hurricane from fixed camera at space(inertail frame ) will looks the same as when camera is rotating with earth?
I am not sure that I understand the question. You understand that rotating the camera makes the video rotate. And that that is all that it does?

You understand that the rotation rate of the hurricane exceeds that of the earth?
 
  • #47
jbriggs444 said:
I am not sure that I understand the question. You understand that rotating the camera makes the video rotate. And that that is all that it does?

You understand that the rotation rate of the hurricane exceeds that of the earth?
You can record video of ball throwing between two person at merry go around with camera moving with him(rotating frame) or you can set camera fixed at Earth (inertial frame)and then record ball at merry go around.you will get different video of ball paths

Same with Earth and hurricane?
 
  • #48
John Mcrain said:
You can record video of ball throwing between two person at merry go around with camera moving with him(rotating frame) or you can set camera fixed at Earth (inertial frame)and then record ball at merry go around.you will get different video of ball paths

Same with Earth and hurricane?
What, exactly, would you be tracking on the hurricane that is the analogue of a ball? No, it is not the same.
 
  • #49
jbriggs444 said:
What, exactly, would you be tracking on the hurricane that is the analogue of a ball? No, it is not the same.
My question is would hurrican rotate like this if we watch at Earth from inertial frame?
 
  • #50
John Mcrain said:
My question is would hurrican rotate like this if we watch at Earth from inertial frame?
Would it rotate like what? Yes, it rotates. Yes, it rotates faster than the Earth. Yes, the inside rotates faster than the outside.

What is it that you are trying to ask?
 
  • #51
jbriggs444 said:
Would it rotate like what? Yes, it rotates. Yes, it rotates faster than the Earth. Yes, the inside rotates faster than the outside.

What is it that you are trying to ask?
In inertial frame coriolis effect don't exist,so why then we agian see wind bend to the right which gives counterclok wise rotation at cyclon even in inertial frame?
If you look at missile form inertial frame ,missile is going in straight line ,so why wind will not do the same?
Why is my question so strange,isnt my question logic?
 
  • #52
jbriggs444 said:
Earth rotates clockwise

I think you mean counterclockwise, at least if you are looking down on the Earth from above the North Pole.
 
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  • #53
John Mcrain said:
In inertial frame coriolis effect don't exist,so why then we agian see wind bend to the right which gives counterclok wise rotation at cyclon even in inertial frame?
If you look at missile form inertial frame ,missile is going in straight line ,so why wind will not do the same?
Why is my question so strange,isnt my question logic?
The individual parcels of wind are doing the same. They move in straight lines unless deflected by a real force.

The individual parcels of wind start at rest relative to a rotating earth. They are already rotating about a common center. If all things were equal (uniform temperature, etc), this would be an equalibrium situation. No wind would be blowing anywhere. The air would stay in a stable rotation, at rest above the rotating Earth. The Earth itself would (and does) relax into an ellipsoidal shape so that the required centripetal acceleration is provided for.

But if you apply a real physical force to draw a air parcels in toward the center of rotation, that inward movement means that their original tangential velocity at a large radius is now a greater tangential velocity at a smaller radius. The rotation rate of all of the parcels about their common center has increased. The air is no longer at rest relative to the rotating Earth. Winds blow.
 
  • #54
haruspex said:
On the contrary, it is crucial here.

Let the gravitational attraction of the Earth on the car be W.
In the frame of the rotating Earth you have to consider the centrifugal and Coriolis forces: https://en.m.wikipedia.org/wiki/Coriolis_force.
The centrifugal force, ##mR\Omega^2##, points up. Here, R is the radius of the Earth and ##\Omega## is its rotation rate.
The Coriolis force is given by ##-2m\vec\Omega\times\vec v##, where v is the velocity of the car in the rotating frame.
If the car were going West to East, this would also point up, giving a net upward force in the rotating frame of ##3mR\Omega^2##. To an observer in that frame, the car has an acceleration ##R\Omega^2## towards the Earth's centre. For all this to add up correctly, the normal force from the ground would have to be ##W-4mR\Omega^2##. Back in the inertial frame, the car's speed is ##2R\Omega##, so the centripetal force is ##4mR\Omega^2##, giving the same result.

But here the car is going East to West, so the Coriolis force points down, and its magnitude is ##2mR\Omega^2##. Gravitational force plus centrifugal plus Coriolis gives a downward total of ##W-mR\Omega^2+2mR\Omega^2=W+mR\Omega^2##. To the observer on the ground, the car's acceleration is the same as in the W to E case, so the normal force must be just ##W##. In the inertial frame the car is stationary, giving the same result.
What is real reason why bullet hit traget high(Eotvos effect) when shoot at east;
1)is bullet hit higher at target,because coriolis has net upward force on bullet
or
2)the target has time to move down during the flight time below what the aiming point was, so the hit is at the top ?
 
  • #55
John Mcrain said:
What is real reason why bullet hit traget high(Eotvos effect) when shoot at east;
1)is bullet hit higher at target,because coriolis has net upward force on bullet
or
2)the target has time to move down during the flight time below what the aiming point was, so the hit is at the top ?
Why does there have to be only one explanation for any given effect?
 
  • #56
John Mcrain said:
What is real reason why bullet hit traget high(Eotvos effect) when shoot at east;
1)is bullet hit higher at target,because coriolis has net upward force on bullet
or
2)the target has time to move down during the flight time below what the aiming point was, so the hit is at the top ?
It depends on your frame of reference. In the frame of reference rotating with the earth, the Eötvös effect (Coriolis) applies and you can consider that the reason. In an inertial frame there is no such effect, but the target is on a curved trajectory.
 
  • #57
haruspex said:
It depends on your frame of reference. In the frame of reference rotating with the earth, the Eötvös effect (Coriolis) applies and you can consider that the reason. In an inertial frame there is no such effect, but the target is on a curved trajectory.
How can I set equation why bullet hit top of target using inertial frame?
I know that bullet absolute velocity is incresed (earth speed + bullet ground speed) so centripetal force is increased also,but centripetal force point down (not up), toward center

?

jbriggs444 said:
Why does there have to be only one explanation for any given effect?
Yes it can be more...
 
  • #58
John Mcrain said:
How can I set equation why bullet hit top of target using inertial frame?
The point from which the bullet is fired has some instantaneous velocity.
The bullet is aimed as though the target had the same velocity, but it doesn't. If firing East, the target's velocity is, from the shooter's perspective, angled slightly down, so by the time the bullet arrives the target will have descended relative to the trajectory.
Conversely, if firing West, the target's velocity is tipped up, causing it to rise above the trajectory.
 
  • #59
John Mcrain said:
I know that bullet absolute velocity is incresed (earth speed + bullet ground speed) so centripetal force is increased
Why do you say that centripetal force is increased? We need to examine that reasoning because it is faulty.
 
  • #60
John Mcrain said:
so centripetal force is increased
Centripetal force is not an extra applied force. It is that component of the resultant of all the forces that are applied that is normal to the velocity. In this case, it is just gravity, and that is not about to change.
What you mean is that in order to hit the target on the anticipated trajectory the centripetal force would need to increase - but it doesn't.
 

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