Free Fall/Constant Acceleration Problem

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SUMMARY

The discussion focuses on solving a physics problem involving a rocket ship accelerating at 9.8 m/s². The user calculated the time to reach one-tenth the speed of light (30,000,000 m/s) and the distance traveled during that time. The initial calculations yielded a time of 3,061,224.49 seconds and a distance of 4.59 x 10^13 meters. However, a correction was noted, indicating that the time calculation was off by a factor of 10, which subsequently affected the distance calculation by a factor of 100.

PREREQUISITES
  • Understanding of kinematic equations, specifically V=Vo+at and X=Xo+Vo*t+(1/2)(a)(t)
  • Basic knowledge of constant acceleration concepts in physics
  • Familiarity with the speed of light (3.0 x 10^8 m/s) and its significance in physics
  • Ability to perform unit conversions and handle scientific notation
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  • Review the derivation and application of kinematic equations in constant acceleration scenarios
  • Learn about relativistic effects when approaching the speed of light
  • Explore the implications of acceleration in space travel and its calculations
  • Practice solving similar physics problems involving acceleration and distance
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Students studying physics, educators teaching kinematics, and anyone interested in the principles of motion under constant acceleration.

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Homework Statement


A rocket ship in free space travels with a constant acceleration equal to 9.8m/s^s.
a)If it starts from rest how long does it take to reach a velocity of one tenth of the speed of light? Note: The speed of light in a vacuum is 3.0 x 10^8 m/s.
b)How far will it travel during this time?


Homework Equations


V=Vo+at
X=Xo+volt+(1/2)(a)(t)


The Attempt at a Solution


I started with making a variable list:
a=9.8 t=?
Vo=0 Xo=0
V=30,000,000 X=?

I plugged these values into the equation I mentioned in # 2.
The answers I got are:
a) 3061224.49sec
b)4.59 x 10^13
I wasn't sure how to do this and gave it a shot. Could you please explain.
Thanks!
 
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Your method is fine, but be careful with decimal points. Your answer for (a) is off by a factor of 10, making (b) off by a factor of 100.
 

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