Free-fall kinematics on a plane: Displacement from Window to Ground?

AI Thread Summary
A ball is thrown upward from a window at 10 m/s and hits the ground after 5 seconds. The initial velocity (Vi) is 10 m/s, final velocity (Vf) is 0, and acceleration (Δa) is -9.8 m/s². The total displacement is calculated using the formula Δd = (Vi + Vf)/2 * Δt, resulting in 25 meters. The user expressed uncertainty about the next steps but later resolved the question independently. The thread has been marked for deletion as the issue was resolved outside the forum.
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Homework Statement


A ball is thrown vertically upward from a window at 10m/s. It hits the ground 5.0 seconds later. What is the height of the window from the ground?

Given
Vi = 10 m/s
Vf = 0
Δt = 5.0 m/s
Δa = -9.8 m/s^2

Find
Δd(w-g) = ?

Homework Equations



Δd = Vi(Δt) + Δa(Δt)^2

And the other four "kinematic equations"

The Attempt at a Solution



Total displacement:

Δd = ((vi + vf)/2)(Δt)

= (10/2)(5)
= 25 m
Not sure where to go from here and if I'm on the right track. Your help is greatly appreciated!

P.S. I apologize for the terrible formatting. I'll get it soon enough!
 
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