Frequency of EM Waves in an LC Circuit

AI Thread Summary
The frequency of electromagnetic (EM) waves produced by an LC circuit can match the frequency of the oscillating current if the circuit is self-resonant; however, it may differ when driven by an external input at a different frequency. In a vacuum tube, the output frequency is influenced by the driving frequency rather than the physical parameters of the circuit. In magnetrons, the EM waves are generated by the oscillation of current and the acceleration of electrons, with the driving magnetic field setting the operational frequency. The geometry of the magnetron cavity plays a role similar to that of the inductance and capacitance in a plate circuit. Ultimately, both the oscillating current and the behavior of electrons contribute to the production of EM waves in these systems.
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Will the frequency of EM waves produced by oscillating current in an LC circuit be the same as the frequency of the current?

Thanks!
 
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It depends on whether the LC circuit is self-resonant (like in a Colpitts oscillator), or whether it is being driven by an external input at an off-resonant frequency. Suppose the plate circuit (of a vacuum tube) is set to 10.0123 MHz, and the grid is being driven at 10.0000 MHz. The EM waves would be at 10.0000 MHz. Furthermore, because the LC resonant circuit is lossy (has a resistive component), this will also detune the LC resonant frequency of the circuit.
 
Hey Bob,

Thanks again for a very helpful reply.

One major question I have:

Are the EM waves produced by the magnetron produced due to oscillations of current in the LRC cavity, or due to the acceleration of the electrons in between the cathode and plate?
 
I am not quite sure what your question is, but the geometry of the magnetron cavity (slot dimensions, etc,) is equivalent to the physical L and C in a plate circuit (of a vacuum tube). The driving frequency in a magnetron is set by the magnitude of the magnetic field, e.g., 875 Gauss for 2.45 GHz (microwave oven). In both the vacuum tube and the magnetron, the driving force (grid signal or magnetic field) and not the physical parameters (L & C or magnetron geometry) determines the outout frequency
 
Bob S said:
I am not quite sure what your question is, but the geometry of the magnetron cavity (slot dimensions, etc,) is equivalent to the physical L and C in a plate circuit (of a vacuum tube). The driving frequency in a magnetron is set by the magnitude of the magnetic field, e.g., 875 Gauss for 2.45 GHz (microwave oven). In both the vacuum tube and the magnetron, the driving force (grid signal or magnetic field) and not the physical parameters (L & C or magnetron geometry) determines the outout frequency

I mean to say, LC circuits produce EM waves due to current oscillation. Is this the source of the microwaves? Or is the source instead, the electrons orbitting the cathode being decelerated/accelerated giving off their energy as EM waves?
 
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You are right. The electrons in the magnetron are a current, and bunches of electrons circulating (at the electron cyclotron frequency) past the vanes in the magnetron produce an EM oscillation in the cavities. An old friend of mine designed the rising sun magnetron for his PH.D. thesis during WW II.
 
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