Frequency of Oscillations of Two Joined Springs and Block of Mass 0.245 kg

AI Thread Summary
The discussion centers on calculating the frequency of oscillation for a system of two springs joined in series, connected to a block of mass 0.245 kg. The original spring constant of 6430 N/m is halved to 3215 N/m due to the series configuration. The frequency is calculated using the formula f = sqrt(k/m)/(2*pi), resulting in 18.23 Hz. Participants also inquire about solving similar problems with non-identical springs. The conversation emphasizes understanding the configuration of springs to determine the effective spring constant.
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Two springs with a spring constant of k = 6430 N/m are joined and connected to a block of mass 0.245 kg. The system is then set oscillating over a frictionless surface. What is the frequency of the oscillations?

This is what I think is the correct approach to this question:

since the springs are joined, the new spring now has a spring constant of 6430/2 = 3215 N/m.

So f = sqrt(k/m)/2*pi

= 18.23 Hz.

Is this correct? Thanks.
 
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apchemstudent said:
Two springs with a spring constant of k = 6430 N/m are joined and connected to a block of mass 0.245 kg. The system is then set oscillating over a frictionless surface. What is the frequency of the oscillations?
This is what I think is the correct approach to this question:
since the springs are joined, the new spring now has a spring constant of 6430/2 = 3215 N/m.
So f = sqrt(k/m)/2*pi
= 18.23 Hz.
Is this correct? Thanks.

Are the springs joined in series, or in parallel?
 
pervect said:
Are the springs joined in series, or in parallel?

they are in series

As well, how would some one solve a problem like this, if the springs were not identical?
 
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