Frictional Force: Calculate on 43 kg Mass Inclined at 19 Degrees

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To calculate the frictional force acting on a 43 kg mass on a 19-degree incline, the coefficients of static and kinetic friction are provided as 0.42 and 0.36, respectively. The normal force can be determined using the formula N = mgcos(θ), while the frictional force is calculated as F_friction = μN. The discussion highlights confusion regarding the correct approach, with suggestions to focus on the gravitational component acting down the incline and to consider the equilibrium state of the block. It is emphasized that since the block is at rest, the forces must balance, confirming that the problem is indeed one of equilibrium. The correct frictional force must be calculated based on these principles.
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Homework Statement



a block is at rest on the incline shown in the figure. the coefficients of static and kinetic friction are s = 0.42 and k = 0.36 respectively. The acceleration of gravity is 9.8 m/s^2. the angle is 19 degrees.

what is the frictional force acting on the 43 kg mass? answer in units of N.

The Attempt at a Solution



I tried brake it up into components and still got it wrong, really have no idea how to do this problem.
 
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The friction coefficient is denoted by: μ
The Normal force is: N=mgcos(θ)
The frictional force is: μN=μmgcos(θ)
 
yea, I get 167.3454417 as my answer (dont have to put it into significant figures for the homework) and its wrong...
 
the angle of inclination is on the left, the object would slide to the left if it wasnt for the friction...if it makes a difference but I also tried to submit my answer as -167.3454417 and that was wrong too...
 
What is the correct answer?
 
I don't know the correct answer because I need to submit the homework online and it gives u like 7 chances, it only says if ur right or wrong
 
Well, if it's looking for an answer in terms of N, and the frictional force is μN, and if μ=0.42, then in terms of N, the answer is 0.42N.
 
its been a long time since i did these types of problems but i think at rest the frictional force would be F=(mew*mg)-mgsin(theta)
 
grouchy said:

Homework Statement



a block is at rest on the incline shown in the figure. the coefficients of static and kinetic friction are s = 0.42 and k = 0.36 respectively. The acceleration of gravity is 9.8 m/s^2. the angle is 19 degrees.

what is the frictional force acting on the 43 kg mass? answer in units of N.

The Attempt at a Solution



I tried brake it up into components and still got it wrong, really have no idea how to do this problem.
This is a duplicate post. I suggest calculating the value of the component of the gravity force acting down the plane. Then apply Newton 1 for bodies at rest to calculate the friction force. HINT: You won't need to know mu.
 
  • #10
so is this problem equilibrium or not?
 
  • #11
xkaibob said:
so is this problem equilibrium or not?
It is given that the block is at rest; hence, yes, it is in equilibrium.
 
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