Frictional force, normal force and coefficient of friction

AI Thread Summary
To calculate the frictional force, normal force, and coefficient of friction for a 0.2kg object on a 35-degree incline, the normal force (Fn) is determined to be 1.61 N using the equation Fn = m x a x cos(θ). Since the block is not accelerating, the net force is zero, indicating that the gravitational force component down the incline equals the frictional force (Ff). To find Ff, one must analyze the forces acting on the object, considering both the incline and the normal direction. A diagram illustrating these forces can aid in visualizing the problem and solving for the coefficient of friction (u).
lisa1991
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Homework Statement



Calculate the frictional force, normal force and coefficient of friction for an 0.2kg object that is lying on a 35 degree incline.


Homework Equations



Ff= u x Fn
F= m x a

The Attempt at a Solution



I managed to get FN= m x a x cos# = -9.81 x 0.2 x cos35 = 1.61 N

I have no idea how to get Ff, but when I work that out I will be able to work out coefficient (u). Thanks for any help
 
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Since the block is not accelerating, the net force must be zero. Look at all the forces, and find their components along the incline and normal to it.
 
sorry also should have mentioned that 35 degrees is the angle the object starts to move down the slope
 
lisa1991 said:
sorry also should have mentioned that 35 degrees is the angle the object starts to move down the slope

Hi lisa1991! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

At 35° the component of gravity overcomes friction, so the forces are equal and opposite. Draw a diagram showing the incline and the direction of the forces involved.
 
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