Frictional Forces on a Rotating System and Disk: Understanding Angular Momentum

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Homework Help Overview

The discussion revolves around the effects of frictional forces on a rotating system when a metal disk is introduced. The problem involves understanding the direction of these forces in relation to the rotation of both the disk and the system.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to determine the correct direction of the frictional force acting on both the disk and the rotating system. There is confusion regarding whether the disk rotates in the same direction as the system or not, and how this affects the frictional forces involved.

Discussion Status

Some participants are exploring different interpretations of the problem, with one suggesting that the disk will rotate clockwise due to friction, while another questions the original poster's understanding of the system's behavior. There is no explicit consensus, but multiple perspectives are being considered.

Contextual Notes

Participants note that the description provided may be incomplete, and there is a reference to an external source that could clarify the experimental setup related to the question.

NasuSama
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Homework Statement



Suppose the system is rotating clockwise when the metal disk is dropped on it. The direction of the frictional force is...

zero on the disk and the system
counter-clockwise on the disk, clockwise on the system
clockwise on the disk, zero on the system
counter-clockwise on the disk zero on the system
zero on the disk, clockwise on the system
clockwise on the disk and the system
counter-clockwise on the disk and the system
clockwise on the disk, counter-clockwise on the system
zero on the disk, counter-clockwise on the system

2. The attempt at a solution

I believe that the answer is:

"counter-clockwise on the disk, clockwise on the system"

But it is not right. I thought that a system keeps turning clockwise, and that when a disk is place on the system, then the frictional force acts counter-clockwise on the disk.
 
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If that is the entire description you're given, I agree with you. Is there more?
 
See:

http://www.physics.qc.edu/files

Check under PH. 145.1 Then, check Trial 1 under the Procedures.

That describes the experiment, which is related to the question I'm asked.
 
This is strange. I read the OP several times before saying I agree with you, but reading it again I don't! Must have got something backwards before.
When the disk is dropped on it is not rotating. Friction will lead to its rotating in the same direction as the system, clockwise. So the force must be clockwise on the disc (and the other way on the system).
 
haruspex said:
This is strange. I read the OP several times before saying I agree with you, but reading it again I don't! Must have got something backwards before.
When the disk is dropped on it is not rotating. Friction will lead to its rotating in the same direction as the system, clockwise. So the force must be clockwise on the disc (and the other way on the system).

That means frictional force goes clockwise while the system goes counterclockwise?
 
NasuSama said:
That means frictional force goes clockwise while the system goes counterclockwise?
In the lab described, the system will tend to slow down when the disk is dropped on it. Therefore friction acts on the system counter to the system's motion.
 

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