Frictionles force problem with hanging mass

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A block of mass M1 (3.70 kg) on a frictionless incline at 30 degrees is connected to a second block of mass M2 (2.30 kg) via a massless pulley. The problem involves finding the acceleration of both blocks, with the equations of motion derived from Newton's second law (F=ma). The tension in the cord and gravitational forces acting on both masses create a system of equations that need to be solved simultaneously. It is noted that the accelerations of both masses are the same, and the direction of movement is determined by comparing the gravitational forces. The discussion emphasizes the need to clarify the force components and equations to solve for the unknowns.
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Homework Statement


A block if mass M1=3.70 Kg on a frictionless plane inclined at 30 degrees is connected by a cord over a massless, frictionless pulley to a second block of mass M2= 2.30Kg. What is the magnitude of acceleration of both blocks?


Homework Equations


F=ma


The Attempt at a Solution



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Fnormal-M1gsin(30)=0
T=M1a
T-M2g=May

Not really sure where to go from here since I have 2 variables T and a.
T-
 
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Shapeup said:

Homework Statement


A block if mass M1=3.70 Kg on a frictionless plane inclined at 30 degrees is connected by a cord over a massless, frictionless pulley to a second block of mass M2= 2.30Kg. What is the magnitude of acceleration of both blocks?


Homework Equations


F=ma


The Attempt at a Solution




Fnormal-M1gsin(30)=0
your geometry/trig is off, it's not the sin function here...
T=M1a
you are missing a force component in this equation
T-M2g=May
..or is it M2g -T = M2ay?? Or does it matter?
Not really sure where to go from here since I have 2 variables T and a.
T-
2 equations, 2 unknowns..are the accelerations of the masses the same?
 
Since M2*g > M1*g*sinθ, M2 moves in the downward direction.
Now write down expression for net force on M1 and M2.
 
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