Functions of Bounded Variation

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SUMMARY

The discussion focuses on proving that if a function \( f \) has a continuous derivative on the interval \([a,b]\), then the variation \( V(f,P) \) for any partition \( P \) satisfies the inequality \( V(f,P) \leq \int_a^b |f'(t)| dt \). This is established by dividing the function into monotone segments and summing the absolute differences, leading to the conclusion that \( V_{ba} \leq \int_a^b |f'(t)| dt \). The proof effectively demonstrates the relationship between bounded variation and the integral of the derivative.

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1. Homework Statement [/b]
If f has a continuous derivative on [a,b], and if P is any partition of [a,b], show that V(f,P)\leq \intablf'(t)l dt. Hence, Vba\leq\intablf'(t)ldt.

Homework Equations


Monotone function \subset BV[a,b]
\sumf(ti+1)-f(ti) = lf(b) - f(a)l



The Attempt at a Solution


Let P = {a=t0 < t1 < ... < tn}. So if we divide our function into monotone segments we have:

V1(f,P) = \sumf(ti+1)-f(ti) = lf(a1) - f(a)l

V2(f,P) = \sumf(ti+1)-f(ti) = lf(a2) - f(a1)l

.
.
.

Vn(f,P) = \sumf(ti+1)-f(ti) = lf(b)- f(an-1)l

Then, treating this segments independently of the whole, we see that

v1(f,P)= lf(a)-f(a1)l=\intablf'(t)ldt = lf(a1) -f(a)l

etc.

Adding them all up V(f,P)= \intablf'(t)l dt, which satisfies our prompt.
 
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