Fundamental Theorem of Calculus problem

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Pacopag
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Homework Statement


The FTC states that
[tex]{d\over{dx}}\int_a^x f(t)dt = f(x)[/tex]
Now, how do I do something like
[tex]{d\over{dx}}\int_a^{g(x)} f(t)dt = ?[/tex]

Homework Equations


The Attempt at a Solution


I know that it has to do with the chain rule, but I forgot my textbook at school and I can't seem to find it online (e.g. Wikipedia).
 
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Pacopag said:

Homework Statement


The FTC states that
[tex]{d\over{dx}}\int_a^x f(t)dt = f(x)[/tex]
Now, how do I do something like
[tex]{d\over{dx}}\int_a^{g(x)} f(t)dt = ?[/tex]


Homework Equations





The Attempt at a Solution


I know that it has to do with the chain rule, but I forgot my textbook at school and I can't seem to find it online (e.g. Wikipedia).

Changing the variable to u, where u = g(x), the integral looks like this:
[tex]{d\over{du}}\int_a^u f(t)dt = f(u)[/tex]

The trouble is, you want [tex]{d\over{dx}}\int_a^u f(t)dt = f(u)[/tex]

So if you want d/dx(H(u)), that's the same as d/du(H(u))*du/dx, isn't it? (Here, H(u) represents the value of the definite integral."