Fundamental Theorem of Calculus

planauts
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Homework Statement


ahRH3.png



Homework Equations





The Attempt at a Solution


I know this is not right.
k3AhJ.png


Could someone help me out here?
Thanks
 
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planauts said:

Homework Statement


ahRH3.png


Homework Equations



The Attempt at a Solution


I know this is not right.
k3AhJ.png


Could someone help me out here?
Thanks
Since u = b(x) your final answer is equivalent to f(b(x))\cdot b'(x)\ .
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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