Fundamental theorem of calculus

nicolauslamsiu
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Homework Statement


Using Fundamental Theorem of Calculus to find the derivative

2. Homework Equations
upper limit=x^2, lower limit=4x

∫ { 1 / [1+ (sin t)^2] }dt

The Attempt at a Solution


two independent variables are involved, how should i find the derivative? [/B]
 
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Let F(x) = \int_{4x}^{x^2} \frac{dt}{1 + \sin^{2}t}, and put G(y) := \int_{0}^{y} \frac{dt}{1 + \sin^{2}t}.

Then, F(x) = G(x^2) - G(4x), by the domain splitting property of the Riemann integral. Does this help things?
 
oo) yup... sure... i think i know how to solve now... thanks
 
nicolauslamsiu said:
two independent variables are involved,
Not really. t is a 'dummy variable' that has no existence outside the integral. The integral as a whole is a function of x only.
 
It's probably worth making an attempt using the first FTC and understanding it.

You could use this,
Set ##F(x) = \int_{\alpha(x)}^{\beta(x)}{ f(t) dt}##. Then,

##F'(x) = f(\beta(x))\beta'(x) - f(\alpha(x))\alpha'(x)##

However it's probably worth understanding the first FTC before jumping into this.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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