Funtion continuity and open sets

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Homework Statement



Suppose that f : (X,d_X) \to (Y,d_Y). If f is continuous,
must it map open sets to open sets? If f does map open sets to
open sets must f be continuous?

Homework Equations





The Attempt at a Solution



The answer to the first question is yes. The answer to the second question I guess is "no". Is this correct? How can I prove it?
 
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Neither is true. For example, a constant function is trivially continuous but maps any set, including any open set, to a singleton set which is not, generally, open.

Conversely, if B has the discrete topology, so that all sets are open, and A is a [0, 1] with the usual topology, the function f(x)= a for all 0\le x< 1/2 and f(x)= b for all 1/2\le 0\le 1, where a and b are distinct points in B, is not continuous but maps open sets to open sets.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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