Understanding Galilean Transformation: A Troubleshooting Guide

AI Thread Summary
The discussion revolves around the confusion in converting coordinates between two observers, one stationary and one moving along the x-axis. The stationary observer perceives an object n units ahead, while the moving observer sees it at n - vt, where v is their relative velocity and t is the elapsed time. The equations presented attempt to relate the coordinates of both observers, but the user struggles to arrive at the correct transformation. Clarification is provided that the relationship should be x' = x - vt, indicating that x' is derived from the stationary observer's x position adjusted for the moving observer's velocity. The key takeaway is understanding the Galilean transformation correctly to resolve the confusion.
xiankai
Messages
31
Reaction score
0
i have trouble taking the equations given, that is the conversion of one coordinate frame to another.

lets assume at the starting point there are two observers (coordinates (x,y,z,t)).

one observer moves in the x direction and the other observer stays still. the observer that moves has the coordinates of x',y',z',t' at any time.

the stationary observer sees an object in the x-direction, n units ahead. for the moving observer, at a particular instant of time, he sees it as n-vt ahead, where v is the relative velocity between the two frames of reference, and t is the time elapsed from the start till the instant.

as the coordinates of object are (x+n,y,z,t) or (x'+n-vt,y',z',t')

hence..

x+n = x'+n-vt

x = x' - vt

x' = x + vt

which isn't the result to be arrived at. can someone help me? i tried doing a search but it seems to elementary a problem to feature as a major stumbling block, couldn't find any topics on it. ><
 
Physics news on Phys.org
xiankai said:
the stationary observer sees an object in the x-direction, n units ahead. for the moving observer, at a particular instant of time, he sees it as n-vt ahead, where v is the relative velocity between the two frames of reference, and t is the time elapsed from the start till the instant.

as the coordinates of object are (x+n,y,z,t) or (x'+n-vt,y',z',t')
You seem to be confusing the meaning of x and x'. If the stationary observer sees the object at x = n, the moving observer sees the object at x' = x - vt = n - vt.

The coordinates of the object are simply (x, y, z, t) and (x', y', z', t'), related by the usual Galilean transformation.
 
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Dear all, in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows. I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (First part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8 and stuck at some statements. It's little bit confused. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. Solution : The surface bound charge on the ##xy## plane is of opposite sign to ##q##, so the force will be...

Similar threads

Replies
52
Views
4K
Replies
3
Views
3K
Replies
3
Views
4K
Replies
13
Views
2K
Replies
53
Views
4K
Replies
7
Views
2K
Replies
2
Views
2K
Replies
2
Views
2K
Back
Top