Solve Galvanic Cell Question Homework

In summary, the cell in question involves converting chemical energy into electrical energy. The correct metal electrode is tin (Sn) and the solution used is a potassium chloride (kCl) solution. Electrons flow towards both half cells, with chlorine (Cl2) being reduced and tin (Sn) being oxidized. The correct half reactions are Sn + 2Cl- → Sn2+ + 2e + Cl2 and Cl2 + 2e → 2Cl-. The cell potential can be calculated using the equation Ecell = Ecathode - Eanode, and the cell notation is Cl2(g)/2Cl-(aq)//Sn(s)/Sn2+(aq). Lastly,
  • #1
TheRedDevil18
408
1

Homework Statement



chem.jpg


Homework Equations





The Attempt at a Solution



Not feeling too confident about these answers,

1.1) Chemical to electrical

1.2) Iron

1.3) Positive

1.4) kCl

1.5) Sn to electrode A

1.6.1) towards Cl2 half cell
1.6.2) towards Sn half cell

1.7.1) Cl2 + 2e → 2Cl-
1.7.2) Sn → Sn2+ +2e
1.7.3) Cl2 + Sn → 2Cl- + Sn2+

1.8) Ecell = Ecathode - Eanode
= 1.36 -(-0.14)
= 1.5V

1.9) Cl2(g)/2Cl-(aq)//Sn(s)/Sn2+(aq)

1.10) Primary cell cannot be recharged while a secondary cell can.
 
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  • #2


I would like to provide some feedback on your answers:

1.1) Chemical to electrical - This is correct, but it would be helpful to explain a bit more about the process of converting chemical energy into electrical energy.

1.2) Iron - This is incorrect. The correct answer is tin (Sn). Tin is the metal electrode in this cell, not iron.

1.3) Positive - This is correct, but again, it would be helpful to explain why one electrode is positive and the other is negative.

1.4) kCl - This is correct, but it would be helpful to specify the concentration of the potassium chloride (kCl) solution.

1.5) Sn to electrode A - This is correct, but it would be helpful to explain why the tin electrode is connected to electrode A.

1.6.1) towards Cl2 half cell - This is correct, but it would be helpful to explain why the electrons are flowing towards the chlorine half cell.

1.6.2) towards Sn half cell - This is correct, but it would be helpful to explain why the electrons are flowing towards the tin half cell.

1.7.1) Cl2 + 2e → 2Cl- - This is correct, but it would be helpful to explain the half reaction and the oxidation state changes that occur.

1.7.2) Sn → Sn2+ +2e - This is correct, but it would be helpful to explain the half reaction and the oxidation state changes that occur.

1.7.3) Cl2 + Sn → 2Cl- + Sn2+ - This is incorrect. The correct equation should be Sn + 2Cl- → Sn2+ + 2e + Cl2. It would be helpful to explain the half reaction and the oxidation state changes that occur.

1.8) Ecell = Ecathode - Eanode - This is correct, but it would be helpful to explain what each term represents and how to calculate the cell potential.

1.9) Cl2(g)/2Cl-(aq)//Sn(s)/Sn2+(aq) - This is correct, but it would be helpful to explain what each component represents in the cell notation and how to interpret it.

1.10) Primary cell cannot be recharged while a secondary cell can. - This is correct, but it would be helpful to explain the difference between primary and secondary cells and why one
 

1) How do I determine the standard cell potential of a galvanic cell?

The standard cell potential of a galvanic cell can be determined by subtracting the standard reduction potential of the cathode from the standard reduction potential of the anode. This value can be found in a table of standard reduction potentials.

2) How do I calculate the cell potential at non-standard conditions?

To calculate the cell potential at non-standard conditions, you can use the Nernst Equation: Ecell = E°cell - (RT/nF)ln(Q), where E°cell is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of moles of electrons transferred, F is Faraday's constant, and Q is the reaction quotient.

3) What is the purpose of a salt bridge in a galvanic cell?

A salt bridge is used in a galvanic cell to maintain electrical neutrality in the half-cells. It allows for the flow of ions between the anode and cathode, preventing the buildup of excess charge and allowing the reaction to continue.

4) How does the concentration of reactants affect the cell potential of a galvanic cell?

The concentration of reactants affects the cell potential of a galvanic cell by changing the reaction quotient Q in the Nernst Equation. As the concentration of reactants increases, Q decreases, resulting in a more positive cell potential. Conversely, a decrease in reactant concentration leads to a more negative cell potential.

5) Can a galvanic cell ever have a negative cell potential?

No, a galvanic cell cannot have a negative cell potential. The standard cell potential for a galvanic cell is always positive, and the Nernst Equation shows that as the reaction proceeds, the cell potential becomes more positive. However, a negative cell potential can occur if the anode and cathode are reversed or if the cell is not constructed properly.

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