# Gauss' Law: Charge distribution on concentric spherical surfaces

Gold Member
You are right.
There was some confusion about the sign of charges. The problem text said that "The sphere has a total charge of 2Q and the shell has a total charge of 3Q."
The charge locates on the surfaces. So there is 2Q charge on the surface of the inner sphere of radius a. By induction, there is -2Q charge on the inner surface of the shell, a sphere of radius b, and to make the total charge of the shell 3Q, there must be 5Q charge on the outer surface of radius c.

Makes sense

Gold Member
Electrons cannot pass air.

This was true

İnide sphere theres 2Q
Outer speher inner surface -2Q
Outer sphere outhere surface 5Q

BvU