(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Non conducting solid cube with a uniform charge distribution. Why is it impossible, or extremely difficult to calculate the field using a larger cube as the gaussian, what about with a sphere as the gaussian?

2. Relevant equations

gauss' law

3. The attempt at a solution

I am guessing this is difficult and nearly impossible, at least at our level in both cases because there isn't a very good way of determining what the field would be at some arbitrary point on the Gaussian surface to sum over the entire surface. I am thinking that a sphere wouldn't be very possible either because of the same problem. And the angle of the field compared to the vector dA would be very difficult to determine aswell since we really have no idea what the heck the shape of this E field would even look like, as there isn't much symmetry to use?

Am I going in the right direction? I don't think I really understand Gauss' law entirely yet but if I can formulate a descent response to this I think that would certainly improve my understanding.

**Physics Forums - The Fusion of Science and Community**

# Gauss' Law with a cube

Have something to add?

- Similar discussions for: Gauss' Law with a cube

Loading...

**Physics Forums - The Fusion of Science and Community**